The relative atomic mass of neon is 20.18 It consists of three isotopes with the masses of 20,21and 22 It consists of 90.5% of NE20 find % ?

Of the other two isotopes ? 

how do I do this in steps ? 

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  • 1 month ago

    Let y% be the relative abundance of Ne-21.

    Then, the relative abundance of Ne-22 = (100 - 90.5 - y)% = (9.5 - y)%

    Relative atomic mass of Ne:

    20 × 90.5% + 21 × y% + 22 × (9.5 - y)% = 20.18

    1810 + 21y + 209 - 22y = 2018

    y = 1

    Relative abundance of Ne-21 = 1%

    Relative abundance of Ne-22 = (9.5 - 1)% = 8.5%

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