Physics II problem?
The electric potential inside a charged spherical conductor of radius R is given by V = keQ/R, and the potential outside is given by V = keQ/r. Using Er = -dV/dr, derive the electric field inside and outside this charge distribution. (Use the following as necessary: ke, Q, r and R.) Should have two answers: (a) inside and (b) outside
- NCSLv 71 month agoFavorite Answer
(a) Inside, the potential is constant and so the field (which is the derivative of potential w/r/t r) is zero --
E = dV/dr = d(-ke*Q/R)/dr = 0
(note that dR/dr = 0 -- R is a constant, not a variable)
E = d(-ke*Q/r)/dr = ke*Q/r²
Hope this helps!