Physics II problem?

The electric potential inside a charged spherical conductor of radius R is given by V = keQ/R, and the potential outside is given by V = keQ/r. Using Er = -dV/dr, derive the electric field inside and outside this charge distribution. (Use the following as necessary: ke, Q, r and R.) Should have two answers: (a) inside and (b) outside

1 Answer

  • NCS
    Lv 7
    1 month ago
    Favorite Answer

    (a) Inside, the potential is constant and so the field (which is the derivative of potential w/r/t r) is zero --

    E = dV/dr = d(-ke*Q/R)/dr = 0

    (note that dR/dr = 0 -- R is a constant, not a variable)

    (b) Outside,

    E = d(-ke*Q/r)/dr = ke*Q/r²

    Hope this helps!

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