Anonymous
Anonymous asked in Science & MathematicsPhysics · 1 month ago

At what rotation rate, in revolutions per second, will the astronaut experience a centripetal acceleration of 17.1g?

NASA's Ames Research Center in Mountain View, California, houses a 20g centrifuge used to conduct research and training to solve real world problems related to the effects of acceleration on systems. It consists of a horizontal rail system with a 58-foot diameter mounted on a central axis, as shown in the figure below. An astronaut is using the centrifuge for training on high accelerations during spaceflight. The astronaut is seated 29.0 ft from the axis of rotation. At what rotation rate, in revolutions per second, will the astronaut experience a centripetal acceleration of 17.1g?

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  • 1 month ago
    Favorite Answer

    29 ft = 8.84 m

    17.1 g = 168 m/s²

    a = ω²r = 168 m/s²

    ω = √(168/8.84) = 4.35 rad/s

    4.35 rad/s x 1 rev/2π rad = 0.693 rev/s

    Centripetal acceleration is

    a = Vdθ/dt = ω²r = Vω = V²/r

       V is the tangental velocity in m/s

       r is radius of circle in meters

       ω is angular velocity in radians/sec = v/r

       a is in m/s²

  • Zirp
    Lv 7
    1 month ago

    that depends on the radius

    Not that it matters, because before you reach 17 G the astronaut will be quite dead

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