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# Calculus question?

I am struggling to do the intitial value problem:

t^2 du/dt = e^(-ut)

My question is on the LHS can get rid of the t^2 by dividing by t^2 on both sides? If i can then i can complete, if not then please assist! Thanks!

### 3 Answers

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- oldprofLv 76 months agoFavorite Answer
Yep, ordinary algebra. Divide both sides by the same value and the equation remains balanced. The LHS still = the RHS. So divide away and enjoy.

- ted sLv 76 months ago
a 1st order nonlinear DE...dividing by t² will not help { don't see anything coming }...I tried w = ut which did not help....SORRY

- Anonymous6 months ago
I hereby give you permission to divide both sides by t^2.

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