Calculus question?

Question

I am struggling to do the intitial value problem:

t^2 du/dt = e^(-ut)

My question is on the LHS can get rid of the t^2 by dividing by t^2 on both sides? If i can then i can complete, if not then please assist! Thanks!

 

Answer 1

Favorite Answer

Yep, ordinary algebra.  Divide both sides by the same value and the equation remains balanced.  The LHS still = the RHS.  So divide away and enjoy.

Answer 2

a 1st order nonlinear DE...dividing by t² will not help { don't see anything coming }...I tried w = ut which did not help....SORRY

Answer 3

I hereby give you permission to divide both sides by t^2.