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# if p(-.6, -.8) is a point on the unit circle in the figure above, what is the exact value of tan(theta)+sin(theta)?

The circle is in the details. thanks

### 3 Answers

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- MichaelLv 71 month ago
opp = y = -0.8

adj = x = -0.6

hyp = Β 1 ( since it's a unit circle)

Tan π½ = opp/adj

Tan π½ = (-0.8) / (-0.6)

Tan π½ = 4/3 <βββββ

Sin π½ = opp/ hyp

Sin π½ = -0.8 / 1

Sin π½ = -4/5

Tan π½ + Sin π½ = 4/3 - 4/5

Tan π½ + Sin π½ = 20/15- 12/15Β

Tan π½ + Sin π½ = 8/15 <βββββ

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