I need help with this practice. use E=MC^2 Please!!!?

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  • 1 month ago

    For question 4, 

    I'm not sure if you can use E=Mc^2 here, but here's my approach.

    To find mass defect you subtract the mass of the protons and neutrons to the nuclear mass

    The nuclear mass of Cobalt is 59.9338 (as given)

    In Cobalt, there is 

    27 protons 

    32 neutrons

    So the mass of the protons and neutrons = 

    27 x 1.00728 = 27.19656u

    32 x 1.00867 = 32.27744u

    27.19656 + 32.27744 = 59.474u

    Now subtract:

    59.9338 - 59.474 = 0.4598u  

    Thus, 0.4598 is the mass defect

    Since one amu = 1.6605402E^-27 kg, multiply the mass defect to get the mass defect in kilograms:

    7.635163839E^-28 

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