Sean asked in Science & MathematicsChemistry · 2 months ago

The solubility of PbCO3(s) in water at a certain temperature is 3.2 × 10–7 mol/L. Calculate the valueof Ksp for BaCO3(s) at this temperature?

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  • 2 months ago

    PbCO₃(s)   ⇌  Pb²⁺(aq)   +   CO₃²⁻(aq)       Ksp = ?

    Eqm:        3.2 × 10⁻⁷ M    3.2 × 10⁻⁷ M

    At equilibrium: Ksp

    = [Pb²⁺] [CO₃²⁻]

    = (3.2 × 10⁻⁷)²

    = 1.0 × 10⁻¹³

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