The space shuttle burned hydrogen and oxygen in its main engine, forming water as a result. The external tank contained 1.3×105 kilograms of hydrogen. How much heat was produced from the combustion of this H2 with excess O2 in a space shuttle launch? The standard enthalpy of formation for one mole of water vapor is approximately –250 kJ/mol of water.
- BobbyLv 71 month ago
2H2+ O2 = 2H2O
mass of H2 = 1.3 * 10 ^5 Kg = 1.3 * 10 ^5 Kg * 10 ^3 / 2.015 g / mol
= 6.45E+07 moles of H2
H2 is the limiting reagent and forms 6.45E+07 moles of H2O ( see equation)
heat produced = 250 kJ/mol * 6.45E+07 moles
we have 1.61* 10 ^10 kJ of heat produced