Math Clock Problem?

An old fashion clock with twelve numbers on the face and hands forms a right angle at 3:00. What is the next time they form a right angle?

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  • 1 month ago
    Favorite Answer

    Hour hand:

    makes one revolution in 12 hours

    in one minute the angles increases by

    360 / (12*60) = 0.5º

    It starts at 3:00 which is 90º

    ϴ₁  = 90 + 0.5m

    ----------------------

    Minute hand

    makes one revoulution in 1 hour

    in one minute the angles increases by

    360 / 60 = 6º

    It starts at 0º

    ϴ₂  = 6m

    ---------------------

    The next time they will be at 90º

    ϴ₂ - ϴ₁ = 90

    6m - (90 + 0.5m) = 90

    5.5m = 180

    m = 32.7272727273

    32 minutes 43.63... seconds

    time will be 

    ~ 3:32:44 <–––––––

  • Anonymous
    1 month ago

    An old-fashioned clock 

    An analog clock 

    90° at 3:00 

    90° at 9:00

    Source(s): Been there
  • 1 month ago

    answer is wind it up so it works correctly..

  • 1 month ago

    9:00 is the next time they form a right angle.

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  • 1 month ago

    12 hours after that

  • 1 month ago

    The ext time would be 4:05.

  • 1 month ago

    Let y min after 3:00 be the next time when the two hands form a right angle.

    The hour hand turns 360°/12 = 30° in 60 min. Hence, in y min it turns 30° × (y/60) = 0.5y°

    The minute hand turns 360° in 60 min. Hence, in y min it turns 360° × (y/60) = 6y°

    When next time the two hands form a right angle, the minutes hand turns 180° more than hour hand:

    6y = 0.5y + 180

    5.5y = 180

    y = 32 and 8/11

    Answer: The time is (32 and 8/11) min ≈ 32.73 min after 3:00. It is about 3:32:44

  • User
    Lv 7
    1 month ago

    at about 3:33

    But let's calculate exactly (as Captain tried and failed to do).

    First, let's remember to put EVERYTHING in the form of minutes.

    We know that the hour hand position will be at 3 o'clock + a location equal to 1/60 times 5 minutes (because the hour hand moves the space of 5 minutes in one hour)

    H = 3 o'clock + 5 * min/60

    where min is the number of minutes past 3 o'clock.

    Remember, we're doing everything in minutes, so 3 o'clock is actually 15 min.

    (eq 1) H = 15 + min/12

    and when the minute hand is at 90 deg to the hour hand it will be 15 minutes ahead of the hour hand position

    (eq 2) min = H + 15

    Use (eq 1) to replace H in (eq 2)

    min = 15 + min/12 + 15

    now solve

    (min - 30) = min/12

    12min - 360 = min

    11min = 360

    min = 32.7

    H = 15 + min/12 = 17.7

    which is a position 15 minutes before the minute hand at 32.7 minutes

  • The hour hand moves at 1/60th of the rate of the minute hand.  When the minute hand travels t degrees, the hour hand will travel t/60 degrees.  The hour hand is at t = 0 when the minute hand is at t = -90

    m = -90 + t

    h = t/60

    We want to know when m = h + 90

    t/60 + 90 = -90 + t

    180 = t - t/60

    180 = 59t/60

    180 * 60/59 = t

    t = 10800 / 59

    t = 183.05084745762711864406779661017....

    But what time does this correspond to?  Well, one revolution is 360 degrees and it's equal to 60 minutes

    60 * t / 360 =>

    t/6 =>

    30.508474576271186440677966101695

    At 3:30:30.50847...., the minute hand and hour hand will be 90 degrees from each other.

    It's kind of neat, a sort of recursion has happened.  I had to check twice to make sure I hadn't accidentally done something wrong.  I had gotten 30.50847.... minutes, so I subtracted 30 from that, which gave me 0.50847.... minutes.  I multiplied that by 60 and got 30.50847... seconds.  I could keep doing that forever.

  • 1 month ago

    at about 3:31            

    in more detail:

    angle of hour hand with vertical is h(360/12) =  30h (0<h≤12)

      where h is hour in hours and decimal minutes

      or angle = 30(h+m/60)

    angle of minute hand is m(360/60) = 6m  (0≤m<60)

    you can plug in numbers

    90º angle

    |30(h+m/60) – 6m| = 90

    for h=3

    30(3+m/60) – 6m = 90

    90 + m/2 – 6m = 90

    m/2 – 6m = 0

    m = 0 (ie 3 hr 0 min)

    or

    |30(h+m/60) – 6m| = 90

    6m – 30(3+m/60) = 90

    6m – 90 – m/60 = 90

    6m – m/60 = 180

    360m/60 – m/60 = 180

    359m/60 = 180

    m = 30.1 min

    ie 3 hr 30.1 min

    but check the math...

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