Anonymous
Anonymous asked in Science & MathematicsChemistry · 2 months ago

Concentration of B at equilibrium? ?

Consider the reaction.

A(aq)↽−−⇀2B(aq)𝐾c=5.85×10−6 at 500 K

 

If a 3.10 M sample of A is heated to 500 K, what is the concentration of B at equilibrium?

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  • 2 months ago
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                   A(aq)   ⇌   2B(aq)   Kc = 5.85 × 10⁻⁶

    Initial:     3.10 M          0 M

    Change:  -y M          +2y M

    Eqm:   (3.10 - y) M     2y M

    At equilibrium:

    Kc = [B]² / A

    5.85 × 10⁻⁶ = (2y)² / (3.10 - y)

    (5.85 × 10⁻⁶)(3.10 - y) = (2y)²

    4y² + (5.85 × 10⁻⁶)y - (1.8135 × 10⁻⁵) = 0

    y = {-(5.85 × 10⁻⁶) + √[(5.85 × 10⁻⁶)² + 4×4×(1.8135 × 10⁻⁵)]} / (2*4)

    y = 2.13 × 10⁻³

    2y = 4.26 × 10⁻³

    [B] at equilibrium = 4.26 × 10⁻³ M

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