Anonymous
Anonymous asked in Science & MathematicsChemistry · 2 months ago

Value of the equilibrium constant? ?

Two reactions and their equilibrium constants are given.

A+2B2C↽−−⇀2C↽−−⇀D𝐾1𝐾2=2.69=0.276

Calculate the value of the equilibrium constant for the reaction D↽−−⇀A+2B.

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  • 2 months ago
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    Method 1:

    A + 2B ⇌ 2C   K₁ = 2.69

    2C ⇌ D           K₂ = 0.276

    Add the above 2 equations, and cancel 2C on the both sides:

    A + 2B ⇌ D     K₃ = K₁K₂

    Reverse the above equation:

    D ⇌ A + 2B     K = 1/K₃

    K = 1/K₃ = 1/(K₁K₂) = 1/(2.69 × 0.276) = 1.35

    ====

    Method 2:

    A + 2B ⇌ 2C   K₁ = [C]²/([A][B]²) = 2.69

    2C ⇌ D           K₂ = [D]/[C]² = 0.276

    D ⇌ A + 2B     K = ?

    K = [A][B]²/[D]

    = ([A][B]²/[C]²) × ([C]²/[D])

    = (1/K₁) × (1/K₂)

    = (1/2.69) × (1/0.276)

    = 1.35

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