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# lim x→0− (sec x − 1) / x ^3?

compute the following limit if it exist.

### 1 Answer

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- Iggy RockoLv 71 month ago
Use L'Hopital's rule:

lim (secx - 1)/x^3 =

x->0-

lim secx tanx/3x^2 = ...use L'Hopital's rule again

x-> 0-

lim (sec^2x tanx + sec^3x)/6x = -∞

x-> 0-

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