Concentration? Chem help?
The rate constant for the reaction is 0.640 M−1⋅s−1 at 200 ∘C.
If the initial concentration of A is 0.00630 M, what will be the concentration after 745 s?
- micatkieLv 71 month ago
The unit of rate constant (k) for an nth-order reaction is M¹⁻ⁿ•s⁻¹.
Now, the unit of k is M⁻¹•s⁻¹.
Hence, 1 - n = -1
Thus n = 2
The integrated rate equation for the second order reaction:
1/[A] = kt + (1/[A]ₒ)
1/[A] = 0.00630×745 + (1/0.640)
[A] = 1.57 × 10⁻³ M