Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

Concentration? Chem help?

The rate constant for the reaction is 0.640 M−1⋅s−1 at 200 ∘C. 

A⟶products

 

If the initial concentration of A is 0.00630 M, what will be the concentration after 745 s?

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  • 1 month ago

    The unit of rate constant (k) for an nth-order reaction is M¹⁻ⁿ•s⁻¹.

    Now, the unit of k is M⁻¹•s⁻¹.

    Hence, 1 - n = -1

    Thus n = 2

    The integrated rate equation for the second order reaction:

    1/[A] = kt + (1/[A]ₒ)

    1/[A] = 0.00630×745 + (1/0.640)

    [A] = 1.57 × 10⁻³ M

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