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# How to do this problem?

A Campbell’s Soup can is 15cm tall and has a radius of 5 cm.

How much paper is needed to make the label (think about what the label covers)?

How much soup can this can hold? (1 cm3 = 1 mL)

### 4 Answers

- MichaelLv 72 months agoFavorite Answer
How much paper is needed to make the label (think about what the label covers)?

a = circumference * height

a = 2πr * h

a = 2π(5) * 15

a = 471.2cm² <––––––

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How much soup can this can hold?

v = area * height

v = πr² * h

v = π(5²) * 15

v = π(25) * 15

v = 1,178cm³

v = 1,178 mL

v = 1.178 L <––––––

- SumDudeLv 72 months ago
get out a soup can and measure up and down, and around, and multiple. {Beats the heck out of learning math formulas.} GO STEM !!

- RRLv 72 months ago
15cm x the circumference of the can will give you the surface area of the side of the can:

C = 2πr

= 2π x 5

= 31.42 cm

31.42 x 15 = 471. 23 cm²

You would need 471. 23 cm² (with no overlap)

____________

You can work out the volume by working out the area of the top or bottom and multiplying by the height;

A = πr²

= π x 5²

= π x 25

= 78.54 cm²

78.54 x 15 = 1178.10 cm cubed = 1178.1 ml = 1.178 Litres

- ?Lv 72 months ago
The base of the can is a circle of radius 5cm.

The circumferene of the base circle is 2πr = 10π cm

The label will be a rectangle with length = 10π cm and width = 15 cm............ANS

Area of the label would be (10π cm)(15 cm) = 150π cm²............ANS

The can of soup can hold πr²h = π5²15 = 375π cm³ = 375π mL...................ANS