precalculus help please?

two loran stations are positioned 270 miles apart along a straight shore. a ship records a time difference of 0.00129 seconds between the loran signals. (The radio signals travel at 186.000 miles per second.) where will the ship reach shore if it were to follow the hyperbola corresponding to this time difference? if the ship is 100 miles offshore, what is the position of the ship?

A. 120 Miles from the master station (100, 228.1)

B. 120 Miles from the master station, (228.1, 100)C. 15 miles from the master station, (100, 228.1)D. 15 miles from the master station, (228.1, 100)

1 Answer

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  • 3 weeks ago

     The ship will reach shore at the distance between the two stations minus the difference in distance between the two, divided by the two. So we have:(252-239.94)/2 = 12.06/2 = 6.03 miles away from the station.

    - the value of a will be difference in distance divided by two, so 239.94/2=119.97;

    a = 119.97, a^2 = 14392.8009

    - the value of c corresponds to the focus of the hyperbola, in this case distance between stations divided by two, therefore c = 252/2 = 126;

    c = 126, c^2 = 15876

    - to find b^2, we use the equation c^2 = a^2 + b^2, so 15876 = 14392.8009 + b^2; b^2 = 15876 – 14392.8009 = 1483.1991

    x^2/a^2 – y^2/b^2 = 1

    x^2/14392.8009 – y^2/1483.1991 = 1

    When ship is 70 miles offshore, y = 70.

    Input value of y into equation to find the value of x:

    x^2/14392.8009 – 70^2/1483.1991 = 1

    x^2/14392.8009 – 2500/1483.1991 = 1

    x^2/14392.8009 = (2500/1483.1991) + 1

    x^2/14392.8009 = 2.68554579085168

    x^2 = 14392.8009*2.68554579085168

    x^2 = 38652. 5258755613

    x = √38652. 5258755613

    x = 196.6024 = ≈197

    The position of the ship when 70 miles offshore is at (228.1 100).

    Source(s): School
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