Anonymous
Anonymous asked in Science & MathematicsPhysics · 4 weeks ago

A kid is on a stationary sled, on snowy ground with Us=0.105. It takes 71.2 N of force to set the sled moving. How much is normal force?

2 Answers

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  • 4 weeks ago

    BY F(friction) = µs x N

    =>71.2 = 0.105 x N

    =>N = 678.10 Newton

  • 4 weeks ago

    Let, the normal force be R N.

    we know,  

    F = R × μ

    here, F = required force = 71.2 N

    R = Normal force .

      μ = coefficient of friction = 0.105

    now putting the values:

    71.2 = R × 0.105

    => R = 678.095 N

    The normal force is 678.095 N

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