Bob asked in Science & MathematicsChemistry · 3 weeks ago

When the following redox equation is balanced correctly in base, what is the coefficient of the N2O4?

N2O4 + Br– → NO2– + BrO3–

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  • 3 weeks ago
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    1. Divide the reaction into its two half-reactions and balance the main atom in each:

    N2O4 --> 2 NO2-

    Br- --> BrO3-

    2. Balance O by adding H2O:

    N2O4 --> 2 NO2-

    Br- + 3 H2O --> BrO3-

    3. Balance H by adding H+:

    N2O4 --> 2 NO2-

    Br- + 3 H2O --> BrO3- + 6 H+

    4. Balance charges by adding electrons:

    N2O4 + 2 e- --> 2 NO2-

    Br- + 3 H2O --> BrO3- + 6 H+ + 6 e-

    5. Multiply half-reaction(s) by a small number to balance electrons:

    3 N2O4 + 6 e- --> 6 NO2-

    Br- + 3 H2O --> BrO3- + 6 H+ + 6 e-

    6. Add the two half-reactions:

    3 N2O4 + Br- + 3 H2O --> 6 NO2- + BrO3- + 6 H+

    So, the coefficient of N2O4 is 3.

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