What is the oxidizing agent in the following oxidation-reduction equation?
H+ + I– + Cr2O72– → Cr3+ + I2 + H2O
- oeman50Lv 73 weeks agoFavorite Answer
Cr2O72-. The Cr is +6 on the left and goes to +3 on the right meaning it is reduced. That makes it the oxidizing agent since it contributes electrons for the oxidation process.
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