If 0.250g of fuel increases the temperature of a calorimeter by 20°C, and the calorimeter is calibrated at 7.28 kJ/°C?

Calculate the heat of combustion of fuel per gram.

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  • 1 month ago

    Bomb calorimeter .....

    heat lost by burning fuel = -heat gained by calorimeter

    q = -CΔT .... where C is the heat capacity of the calorimeter (7.28 kJ/C)

    q = -7.28 kJ/C x 20C = -145.6 kJ

    heat of combustion = -145.6 kJ / 0.250g = -582 kJ/g

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