If 0.250g of fuel increases the temperature of a calorimeter by 20°C, and the calorimeter is calibrated at 7.28 kJ/°C?
Calculate the heat of combustion of fuel per gram.
- fmcarajoLv 71 month ago
Bomb calorimeter .....
heat lost by burning fuel = -heat gained by calorimeter
q = -CΔT .... where C is the heat capacity of the calorimeter (7.28 kJ/C)
q = -7.28 kJ/C x 20C = -145.6 kJ
heat of combustion = -145.6 kJ / 0.250g = -582 kJ/g