Help with Arithmetic Series?
Corey is deciding between two summer jobs. He plans to work from May to August, inclusive.
First job pays $1500/month with a monthly raise of $150
Second job pays $300/week with a weekly raise or $15
a. Determine the total income earned if Corey takes the first job
b. How many weeks are there during this time period
c. Determine the total income earned if Corey takes the second job
- PhilomelLv 71 month ago
from May to August (July 31) is 3 months, 13 weeks.
Job1 $4,950. 13 weeks. Job 2 $5,100.
- Wayne DeguManLv 71 month ago
To make the arithmetic a little easier we will assume the duration is 3 months or 12 weeks
(Job 1) We have an arithmetic series with first term 1500 and common difference 150
so, S₃ = (3/2)[3000 + 2(150)] = (3/2)[3000 + 300)
(Job 2) We have an arithmetic series with first term 300 and common difference 15
so, S₁₂ = (12/2)[600 + 11(15)] = 6[600 + 165]
Therefore, earning $360 more doing the first job.
- billrussell42Lv 71 month ago
May to Aug is 4 months, and 31•3+30 = 123 days, or 17 weeks 4 days
unclear if you want me to use 17 or 18 weeks
also depends on when pay week starts and ends, on which day....
first job pays 1500+1650+1800+1950 = 6900 or 1500•4 + 150•6 = 6900sec job pays (at 17 weeks)
use sum of series, d=15, a = 300, n = 17
S = (n/2)(2a+d(n–1)) = (17/2)(2•300+15(16)) = 8.5(600+225) = 7140
(18/2)(2•300+15(18)) = 9(600+270) = 7830
Arithmetic Series is a sequence of numbers such that the
difference between the consecutive terms is constant.
a + (a+d) + (a+2d) + (a+3d) + ...
Sum of first n terms is
S = (n/2)(a + an)
S = (n/2)(2a+d(n–1))
where an is the nth term
- KrishnamurthyLv 71 month ago
Corey is deciding between two summer jobs.
He plans to work from May to August, inclusive.
The first job pays $1500/month with a monthly rise of $150.
The second job pays $300/week with a weekly raise of $15.
The total income earned if Corey takes the first job is $6450.
There are 17 weeks during this time period.
The total income earned if Corey takes the second job is $5355.