Determine the time taken for the speed to decrease from 12 m/s to 8 m/s?
- oubaasLv 71 month agoFavorite Answer
time t = ΔV/a = (8-12)/a
time depends upon the acceleration a :
if a = -1 m/sec^2 , then t = -4/-1 = 4.0 sec
if a = -4 m/sec^2 , then t = -4/-4 = 1.0 sec
....and so on
- MorningfoxLv 71 month ago
I can do that in less than 12 parsecs!
- NCSLv 71 month ago
What's the acceleration? If its magnitude is "a," then
time t = (12 - 8)m/s / a
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