Can someone please help and explain, thank you its for Statics?
- RealProLv 71 month ago
The moment of inertia of a rectangle of sides p and q, about the axis through its center parallel to the "p" side is
So about the x-axis
The moment of inertia of the horizontal piece is
And of the vertical piece
If we add these two we will be counting the little square in the center twice, so to get the total moment of inertia, subtract c^4 / 12.
I_x = (c/12) [ (2a+c)c^2 + (2b+c)^3 - c^3 ]
Clearly it would be best to work with your dimensions in cm so that the units are cm^4, if it's allowed.