Can someone please help and explain, thank you its for Statics?

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  • 1 month ago

    The moment of inertia of a rectangle of sides p and q, about the axis through its center parallel to the "p" side is

    (1/12)pq^3

    So about the x-axis

    The moment of inertia of the horizontal piece is

    (1/12)(2a+c) c^3

    And of the vertical piece

    (1/12)c(2b+c)^3

    If we add these two we will be counting the little square in the center twice, so to get the total moment of inertia, subtract c^4 / 12.

    I_x = (c/12) [ (2a+c)c^2 + (2b+c)^3 - c^3 ]

    Clearly it would be best to work with your dimensions in cm so that the units are cm^4, if it's allowed.

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