Two blocks are connected by a string over a frictionless pulley. Find acceleration of the blocks and the tension of the strings. ?
Assume the string is weightless.
- NCSLv 71 month agoFavorite Answer
net force = motive force - resistive force
Fnet = weight on incline - friction on incline and horizontal
Fnet = [2.0kg*sin30º - 0.14*(2.0kg*cos30º + 0.80kg)] * 9.8m/s²
Fnet = 6.33 N
acceleration a = Fnet / M = 6.33N / 2.8kg = 2.26 m/s² ◄
which ought to be rounded to 2.3 m/s² imo
consider the top mass
Fnet = T - f
0.80kg * 2.26m/s² = T - 0.14*0.80kg*9.8m/s²
tension T = 2.9 N ◄
Hope this helps!
- oubaasLv 71 month ago
Moving force MF = 2*g*sin 30° = 9.807 N
resistent force RF = g*μk*(0.8+2*cos30°) = 9.807*0.14*(0.8+2*0.866) = 3.477 N
accelerating force AF = MF-RF = 6.33 N
acceleration a = AF/(m1+m2) = 6.33/2.8 = 2.26 m/sec^2
tension T = 0.8*(9.807*0.14+2.26) = 2.91 N