How many nickels are in the jar? ?

A jar contains 68 coins consisting of nickels and dimes, worth a total of $4.65. How many nickels are in the jar? 

8 Answers

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  • 4 months ago

    let x - number of nickels

     y - number of dimes

     0.10[x + y = 68]      

    0.05x + 0.10y = 4.65

    -----------------------------

    0.10x + 0.10y = 6.8

    -[0.05x + 0.10y = 4.65]

    ---------------------------------

    0.05x = 2.15

     x = 43 nickels   Answer//

  • 4 months ago

    LET THE NO OF NICKELS BE  X

    THEN THE NO OF DIMES = 68- X

    VALUE = 0.05X + 0.10 ( 68-X ) = 4.65

    0.05X + 6.80 - 0.10X = 4.65

    0.05X = 2.15

    X = 43

    ANSWER 43 NICKELS

    CHECK

    43 X 0.05 = $2.15

    25 X 0.10 = $ 2.50

    ADD = $ 4.65

  • 4 months ago

    Let

    x=the number of nickels.

    0.05x+0.1(68-x)=4.65

    =>x=43

    Thus, the number of nickels is 43;

    the number of dimes is 68-43=25.

  • Anonymous
    4 months ago

    A jar contains 68 coins consisting of nickels and dimes

    (i) n + d = 68

    worth a total of $4.65.

    (ii) 5n + 10d = 465

    eliminate d by multiplying (i) by 10

    (iii) 10n + 10d = 680

    Subtract (ii) from (iii)

    (iv)5n = 215

    n = 43

    43 nickels

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  • 4 months ago

    A jar contains 68 coins consisting of nickels and dimes, worth a total of $4.65. 

    How many nickels are in the jar? 

    n + d = 68

    5n + 10d = 465

    5n + 5d =340

    5d = 125

    d = 25

    n = 68 - 25 = 43

  • sepia
    Lv 7
    4 months ago

     A jar contains 68 coins consisting of nickels and dimes, worth a total of $4.65. 

     n + d = 68

     5n + 10d = 465

     10n + 10d = 680

     5n = 215

     There are 43 nickels in the jar.

  • 4 months ago

    Let's work in cents rather than dollars.

    Let n be the number of nickels

    Let d be the number of dimes

    Write two equations:

    n + d = 68

    5n + 10d = 465

    Let's divide the last equation by 5:

    n + 2d = 93

    Subtract the first equation:

    n + 2d = 93

    n + d = 68

    ----------------

    d = 25

    Then solve for n:

    n = 68 - 25

    n = 43

    Double-check:

    43 * 5¢ = $2.15

    25 * 10¢ = $2.50

    ---- ........... --------

    68 coins = $4.65

    Answer:

    43 nickels (and 25 dimes)

  • 4 months ago

    x - nickels quantity

    y - dimes quantity

    .05x + .1y = 4.65

    x + y = 68

    .05x + .1y = 4.65

    -.05x - .05y = -3.4

    ---------------------------

              .05y  =  1.25

    y = 1.25 / .05

    y = 25 dimes

    x + 25 = 68

    x = 68 - 25

    x = 43 nickles

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