Kayla asked in Science & MathematicsMathematics · 4 months ago

# How many nickels are in the jar? ?

A jar contains 68 coins consisting of nickels and dimes, worth a total of \$4.65. How many nickels are in the jar?

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• 4 months ago

let x - number of nickels

y - number of dimes

0.10[x + y = 68]

0.05x + 0.10y = 4.65

-----------------------------

0.10x + 0.10y = 6.8

-[0.05x + 0.10y = 4.65]

---------------------------------

0.05x = 2.15

• 4 months ago

LET THE NO OF NICKELS BE  X

THEN THE NO OF DIMES = 68- X

VALUE = 0.05X + 0.10 ( 68-X ) = 4.65

0.05X + 6.80 - 0.10X = 4.65

0.05X = 2.15

X = 43

CHECK

43 X 0.05 = \$2.15

25 X 0.10 = \$ 2.50

• 4 months ago

Let

x=the number of nickels.

0.05x+0.1(68-x)=4.65

=>x=43

Thus, the number of nickels is 43;

the number of dimes is 68-43=25.

• Anonymous
4 months ago

A jar contains 68 coins consisting of nickels and dimes

(i) n + d = 68

worth a total of \$4.65.

(ii) 5n + 10d = 465

eliminate d by multiplying (i) by 10

(iii) 10n + 10d = 680

Subtract (ii) from (iii)

(iv)5n = 215

n = 43

43 nickels

• 4 months ago

A jar contains 68 coins consisting of nickels and dimes, worth a total of \$4.65.

How many nickels are in the jar?

n + d = 68

5n + 10d = 465

5n + 5d =340

5d = 125

d = 25

n = 68 - 25 = 43

• sepia
Lv 7
4 months ago

A jar contains 68 coins consisting of nickels and dimes, worth a total of \$4.65.

n + d = 68

5n + 10d = 465

10n + 10d = 680

5n = 215

There are 43 nickels in the jar.

• 4 months ago

Let's work in cents rather than dollars.

Let n be the number of nickels

Let d be the number of dimes

Write two equations:

n + d = 68

5n + 10d = 465

Let's divide the last equation by 5:

n + 2d = 93

Subtract the first equation:

n + 2d = 93

n + d = 68

----------------

d = 25

Then solve for n:

n = 68 - 25

n = 43

Double-check:

43 * 5¢ = \$2.15

25 * 10¢ = \$2.50

---- ........... --------

68 coins = \$4.65

43 nickels (and 25 dimes)

• 4 months ago

x - nickels quantity

y - dimes quantity

.05x + .1y = 4.65

x + y = 68

.05x + .1y = 4.65

-.05x - .05y = -3.4

---------------------------

.05y  =  1.25

y = 1.25 / .05

y = 25 dimes

x + 25 = 68

x = 68 - 25

x = 43 nickles