## Trending News

Promoted

# Math Help Please!?

Update:

Answer Choices:

3.96 bits

3.06 bits

4.26 bits

2.64 bits

### 1 Answer

Relevance

- 4 months ago
log[2](1/0.16)

log[2](0.16^(-1))

-1 * log[2](0.16)

-1 * log[2](16/100)

-1 * log[2](16) + log[2](100)

log[2](100) - log[2](16)

log[2](100) - 4

log[2](100) =>

2 * log[2](10) =>

2 * log(10) / log(2)

log(2) = 0.301, roughly

2 * 1 / 0.301

2/0.301

2000/301

301 * 6 = 1806

2000 - 1806 = 194

6 + 194/301 - 4 =>

2 + 194/301

301 is pretty close to 300, so we can approximate a little more

2 + 194/300

2 + 1.94/3

2 + 0.646666666666....

2.64

Or we could just use a calculator

log[2](1 / 0.16) =>

log(0.16^(-1)) / log(2) =>

-1 * log(0.16) / log(2) =>

2.6438561897747246957406388589788

2.64

Still have questions? Get your answers by asking now.