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# Can someone help me with this math question?

Given the points M(-3, -5) R(4, 9) and L(-5, 2)...?

a) Determine the equation of the line that passes through L and is parallel to MR.b) Determine the equation of the line that passes though R and is perpendicular to ML.

### 2 Answers

- AshLv 74 months agoFavorite Answer
a) Find slope of line MR

slope, m = (y₂-y₁)/(x₂ x₁) = (9-(-5))/(4-(-3)) = 14/7 = 2

So slope of line parallel to MR = 2

Now using point L

Then equation of required line is y - 2 = 2(x-(-5))

y - 2 = 2(x+5)

y - 2 = 2x + 10

y = 2x + 12 ↢ (In slope-intercept form)

b) Find slope of line ML

slope, m = (2-(-5))/(-5-(-3)) = 7/-2 = - 7/2

So slope of line perpendicular to ML = 2/7 ( negative reciprocal of slope of ML)

Now using point R

Then equation of required line is y - 9 = (2/7)(x-4)

y - 9 = (2/7)x - 8/7

y = (2/7)x + 9 - (8/7)

y = (2/7)x + 55/7 ↢ (In slope-intercept form)