Can someone help me with this math question?

Given the points M(-3, -5) R(4, 9) and L(-5, 2)...?

a) Determine the equation of the line that passes through L and is parallel to MR.b) Determine the equation of the line that passes though R and is perpendicular to ML.

2 Answers

Relevance
  • Ash
    Lv 7
    4 months ago
    Favorite Answer

    a) Find slope of line MR

    slope, m = (y₂-y₁)/(x₂ x₁) = (9-(-5))/(4-(-3)) = 14/7 = 2

    So slope of line parallel to MR = 2

    Now using point L

    Then equation of required line is y - 2   = 2(x-(-5))

    y - 2 = 2(x+5)

    y - 2 = 2x + 10

    y = 2x + 12  ↢ (In slope-intercept form)

    b) Find slope of line ML

    slope, m = (2-(-5))/(-5-(-3)) = 7/-2 = - 7/2

    So slope of line perpendicular to ML = 2/7    ( negative reciprocal of slope of ML)

    Now using point R 

    Then equation of required line is y - 9 = (2/7)(x-4)

    y - 9 = (2/7)x - 8/7

    y  = (2/7)x + 9 - (8/7)

    y = (2/7)x + 55/7 ↢ (In slope-intercept form) 

  • ted s
    Lv 7
    4 months ago

    y - 2 = 2 ( x + 5)  and y - 9 = (2/7) ( x - 4 )

Still have questions? Get your answers by asking now.