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- davidLv 71 month ago
a. find intersection

x^2 = 6 - x

x^2 + x - 6 = 0 ... (x + 3)(x - 2) = 0 ... x = 2 ... x = -3

those are the limits of integration

integrate [-3,2] ((6 - x)-x^2) dx

= integrate [-3,2] (-x^2 - x + 6) dx

= -(1/3)x^3 - (1/2)x^2 + 6x << eval [2, - 3]

= 17/6 <<< answer

now you try the others

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