Anonymous
Anonymous asked in Science & MathematicsMathematics · 8 months ago

Helppppppppp?

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  • Alvin
    Lv 4
    8 months ago
    Favorite Answer

    Volume =pih(r_outer^2 - r_inner^2) 

    V  = 6pi( r_outer^2 - (3)^2 )

    V = 6pi(r_outer^2 -9) 

    dV/dr  =12pi(r_outer)  

    dV/dt = dV/dr * dr/dt  

    so when r_outer = 4.5 cm 

    dV/dr = 12pi(4.5) = 54pi  cm^3/ cm 

    dr/dt =   0.04  cm/hour 

    dV/dt =  54pi cm^3/cm * 0.04 cm/hour =  2.16pi cm^3/hour

    dV/dt =  6.785840132

     dV/dt = 6.786  cm^3/hour 

  • ted s
    Lv 7
    8 months ago

    you haven't even tried this problem !!!...appears to be a ' ring ' of ice with

    volume of V = 6π ( r² - 3²)........dV / dt = 6π ( 2 r dr/dt  )...you finish

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