Math: law of sines, help?

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  • 4 months ago
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    Law of Sines:  (sin A) / a = (sin B) / b = (sin C) / c

    All three of those ratios are equal.  Pick the two that have all of your givens, then solve for the missing one.  You're given b, c, and sin B; so pick the last two:

    (sin B) / b = (sin C) / c

     c (sin B) / b = sin C                  The multiply both sides by c to get sin C alone

     sin C = (c * sin B) / b = (3 * 0.4) / 6

    Without a calculator even, I can see that answer (A) is the one. (...but you might want to double-check that, since it's your grade! :^)

  • 4 months ago

    Apply law of Sines

    ....b.............c

    --------- = ----------

    .sin(B)......sin(C)

    ...6..............3

    -------- = -----------

    ..0.4.........sin(C)

    6sin(C) = 1.2

    sin(C) = 0.2 Answer//

    Answer is A. 0.2..

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