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- husoskiLv 74 months agoFavorite Answer
Law of Sines: (sin A) / a = (sin B) / b = (sin C) / c

All three of those ratios are equal. Pick the two that have all of your givens, then solve for the missing one. You're given b, c, and sin B; so pick the last two:

(sin B) / b = (sin C) / c

c (sin B) / b = sin C The multiply both sides by c to get sin C alone

sin C = (c * sin B) / b = (3 * 0.4) / 6

Without a calculator even, I can see that answer (A) is the one. (...but you might want to double-check that, since it's your grade! :^)

- Engr. RonaldLv 74 months ago
Apply law of Sines

....b.............c

--------- = ----------

.sin(B)......sin(C)

...6..............3

-------- = -----------

..0.4.........sin(C)

6sin(C) = 1.2

sin(C) = 0.2 Answer//

Answer is A. 0.2..

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