An oxide of lead contains 90.65% Pb, by weight. The empirical formula is:(a) Pb(b) PbO(c) Pb3O4(d) Pb2O3(e) PbO2?
- Roger the MoleLv 71 month agoFavorite Answer
Take a hypothetical sample of exactly 100 grams:
(90.65 g Pb) / (207.21 g Pb/mol) = 0.4375 mol Pb
(100 g - 90.65 g) / (15.99943 g O/mol) = 0.5844 mol O
Divide by the smaller number of moles:
(0.4375 mol Pb) / 0.4375 mol = 1.000
(0.5844 mol O) / 0.4375 mol = 1.336
In order to achieve integer coefficients, multiply by 3, then round to the nearest whole numbers to find the empirical formula:
So answer (c).