An oxide of lead contains 90.65% Pb, by weight. The empirical formula is:(a) Pb(b) PbO(c) Pb3O4(d) Pb2O3(e) PbO2?

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  • 1 month ago
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    Take a hypothetical sample of exactly 100 grams:

    (90.65 g Pb) / (207.21 g Pb/mol) = 0.4375 mol Pb

    (100 g - 90.65 g) / (15.99943 g O/mol) = 0.5844 mol O

    Divide by the smaller number of moles:

    (0.4375 mol Pb) / 0.4375 mol = 1.000

    (0.5844 mol O) / 0.4375 mol = 1.336

    In order to achieve integer coefficients, multiply by 3, then round to the nearest whole numbers to find the empirical formula:

    Pb3O4

    So answer (c).

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