Find the number of neutrons released when 132 Sn and 101 Mo are released as fission fragments.?
- hcbiochemLv 72 months agoFavorite Answer
Fission fragments from what? Without knowing the original nucleid, there is no way to know. You can figure out the original element, though:
132/50 Sn and 101/42 Mo mean that the atomic number of the original nucleid (assuming fission was induced by a neutron) would have to be ?/92U.
Assuming that the original isotope was 235/92 U and fission was induced by one neutron, that would give 236 - (132+101) = 3.
So, 3 neutrons would have been released in this fission.