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# slant asymptote?

Using long division, you can calculate that

f(x)=2x^(3)−16x^(2)+7x−39/2x2+5=Q(x)+(R(x)/2x^(2)+5)

The quotient Q(x) is _____

.

The remainder R(x) is _________

.

From this you can conclude that y=f(x) has an oblique (or slant) asymptote given by the line with equation y = _________

?

because limx→±∞R(x)/2x^(2)+5=________

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- ted sLv 71 month agoFavorite Answer
I think you should get x - 8 And 2x + 1....then y = x - 2 & 0

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