bob asked in Science & MathematicsChemistry · 1 month ago

Chemistry equilibrium question?

Attachment image

2 Answers

Relevance
  • david
    Lv 7
    1 month ago
    Favorite Answer

    k1 = k^(1/2)

    k2 = 1/k

    k3  =  (1/k)^(1/2)

    • Commenter avatarLogin to reply the answers
  • Anonymous
    1 month ago

    Solids and liquids are not included in the equilibrium contant.

     

    For the first one, K = [O2]^(3/2) / { [CO2] * [H2O]^2 }

     

    Repeat for the second and third one.

    • Commenter avatarLogin to reply the answers
Still have questions? Get your answers by asking now.