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# How many formula units of iron(III) oxide can be produced from the reaction of 108 g of iron with 72.1 L of oxygen gas at STP?

How many formula units of iron(III) oxide can be produced from the reaction of 108 g of iron with 72.1 L of oxygen gas at STP? ____4___ Fe + ____3___ O2 🡪 ____2___ Fe2O3

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- hcbiochemLv 72 months agoFavorite Answer
72.1 L O2 / 22.4 L/mol = 3.22 mol O2

108 g Fe / 55.845 g/mol = 1.93 mol Fe

1.93 mol Fe X (3 mol O2/4 mol Fe) = 1.45 mol O2 to react completely with available Fe. So, Fe is the limiting reactant

1.93 mol Fe X (2 mol Fe2O3 / 4 mol Fe) X 6.022X10^23 FU/mol = 5.82X10^23 formula units Fe2O3

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- 2 months ago
4 Fe + 3 O2 = 2 Fe2O3

108/ 55.845 moles of Fe + 72.1 / 22.4 moles of O2 react

1.93 moles of Fe react with 1.45 mol od O2 according to the equation

but we have 3.22 moles so Fe is in excess and forms 1.93/ 2 moles of the oxide

in this case formula units of Fe2O3 formed = 0.967 formula units

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