Physics question on temperature ?

In a calorimeter, where there are 200 g of water at a temperature of 20 ° C, 300 g of water is poured at a temperature of 100 ° C. What is the final temperature of the 500 g of water, assuming that heat losses are negligible?

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  • 1 month ago
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    Let the final temperature of the 500 g of water is t*C, by the law of energy conservation:

    =>Q(loss by 100*C water) = Q(gain by 20*C water) 

    =>300 x 10^-3 x 4200 x (100 - t) = 200 x 10^-3 x 4200 x (t - 20) 

    =>300 - 3t = 2t - 40

    =>5t = 340

    =>t = 68*C

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