# Here’s the figure/blueprint of the circuit. Each consumers obstacle is 30 Ω, ammeter obstacle is irrelevant(very small).?

Electromotive force source’s internal resistance/obstacle is 10 Ω, electromotive force is 9V(volts)

a) Calculate the circuits outer parts obstacle and the current which goes through ammeter

b)Calculate the voltage between P and Q, calculate the current through both branches.

c)Calculate the power for each consumer/person

d) Calculate electromotive force source efficiency factor Relevance
• Two resisters are in series

=>R1 = 30 + 30

=>R1 = 60Ω

Now R1 & 30 are in parallel

=>1/R = 1/30 + 1/60

=>R = 20Ω --------------------Answer for (a)

=>Total resistance = R + r = 20 + 10 = 30Ω

Thus by E = iR

=>i = E/R = 9/30 = 0.3 amp --------------------Answer for (a)

Thus by E = V + ir

=>V = 9 - 0.3 x 10

=>V = 6 Volt-------------Answer for (b)

By V = i1R1

=6 = i1 x 60

=>i1 = 0.1 amp------------Answer for (b)

=>i2 = 0.2 amp------------Answer for (b)

BY P = Vi

=>P1 = 6 x 0.1 = 0.6 Watt (for two consumers in series)------------Answer for (c)

& P2 = 6 x 0.2 = 1.2 Watt-----------Answer for (c)

By Efficiency (ƞ) = [output/input] x 100%

=> ƞ = [6/9] x 100% = 66.67%-----------Answer for (d)

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