Here’s the figure/blueprint of the circuit. Each consumers obstacle is 30 Ω, ammeter obstacle is irrelevant(very small).?

Electromotive force source’s internal resistance/obstacle is 10 Ω, electromotive force is 9V(volts)

a) Calculate the circuits outer parts obstacle and the current which goes through ammeter

b)Calculate the voltage between P and Q, calculate the current through both branches.

c)Calculate the power for each consumer/person

d) Calculate electromotive force source efficiency factor

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1 Answer

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  • 2 months ago

    Two resisters are in series

    =>R1 = 30 + 30

    =>R1 = 60Ω

    Now R1 & 30 are in parallel

    =>1/R = 1/30 + 1/60

    =>R = 20Ω --------------------Answer for (a)

    =>Total resistance = R + r = 20 + 10 = 30Ω

    Thus by E = iR

    =>i = E/R = 9/30 = 0.3 amp --------------------Answer for (a)

    Thus by E = V + ir

    =>V = 9 - 0.3 x 10

    =>V = 6 Volt-------------Answer for (b)

    By V = i1R1

    =6 = i1 x 60

    =>i1 = 0.1 amp------------Answer for (b)

    =>i2 = 0.2 amp------------Answer for (b)

    BY P = Vi

    =>P1 = 6 x 0.1 = 0.6 Watt (for two consumers in series)------------Answer for (c)

    & P2 = 6 x 0.2 = 1.2 Watt-----------Answer for (c)

    By Efficiency (ƞ) = [output/input] x 100%

    => ƞ = [6/9] x 100% = 66.67%-----------Answer for (d)

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