- KennyBLv 71 month ago
4Fe(s) + 3O2 --> 2Fe2O3
As for the limiting reagent (or the one in excess), I used the information after the question.
10 g Fe is how many moles? - divide by the atomic weight.
10 g O2 is how many moles? - divide by the molecular weight
Knowing that you need 4 moles of Fe for every 3 moles of O2, which is limiting and which is in excess? How much, then, is in excess? (I can't tell if they will accept the answer in ,moles or if you need to convert back to grams.)