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How do you prepare 0,1N H3PO4 solution using %80 H3PO4 stock solution? (d=1,633g/ml , H:1 O:16 P:31)?

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  • david
    Lv 7
    1 day ago
    Favorite Answer

    1.633g/mL  X (80gsolute/100g soln) /  (82/3 g/n)  X  1000 mL/L  =  47.795N  ,<<<  original conc.

    Now you must dilute this with more water ..  Usually these problems ask you to make 100 mL of the 0.1 N solution  ..  or 500 mL  ... or 1.0 L ...  but you did not specify any set volume.  I will use 1.00 L for the final vol.

        This gives  a dilution equation

         V X N <<  original =  V X N << dilute

        V (47.795N)  =  1000 mL X 0.10 N

         V = 2.092264 mL  <<<

       so use 2.092264 mL  of the conc. solution and add to about 500 ml  water (always add conc. acid to water)  ...  then finish diluting to a total volume of 1000 mL.

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    • david
      Lv 7
      1 day agoReport

      82 is the molar mass .. divide by 3 because 3 H+  from H3PO4  ...  g is grams . /n is per normal.

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