# How do you prepare 0,1N H3PO4 solution using %80 H3PO4 stock solution? (d=1,633g/ml , H:1 O:16 P:31)?

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- davidLv 71 day agoFavorite Answer
1.633g/mL X (80gsolute/100g soln) / (82/3 g/n) X 1000 mL/L = 47.795N ,<<< original conc.

Now you must dilute this with more water .. Usually these problems ask you to make 100 mL of the 0.1 N solution .. or 500 mL ... or 1.0 L ... but you did not specify any set volume. I will use 1.00 L for the final vol.

This gives a dilution equation

V X N << original = V X N << dilute

V (47.795N) = 1000 mL X 0.10 N

V = 2.092264 mL <<<

so use 2.092264 mL of the conc. solution and add to about 500 ml water (always add conc. acid to water) ... then finish diluting to a total volume of 1000 mL.

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82 is the molar mass .. divide by 3 because 3 H+ from H3PO4 ... g is grams . /n is per normal.