jenna asked in Science & MathematicsPhysics · 2 months ago

Help!!!!!!!!!?

A solid ball has a radius of 0.110 m, and a mass of 1.88 kg. How much force must be applied to the edge to give it an angular acceleration of 3.09 9rad/s^2?

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  • 2 months ago
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    torque = τ = Fd = F(0.11)

    assuming the sphere is rotating around a diameter...

    I = (2/5)MR² = (0.4)(1.88)(0.11)²

    α = τ/I

    τ = αI =  (3.09)(0.4)(1.88)(0.11)² = F(0.11)

    F = (3.09)(0.4)(1.88)(0.11)²/(0.11)

    F = (3.09)(0.4)(1.88)(0.11) newtons

    you have a calculator....

    angular acceleration in rad/s²

      α = τ/I for constant α

         I = moment of inertia in kg•m²

         τ = torque in N•m

    I is moment of inertia in kg•m²

    I = cMR²

        M is mass (kg), R is radius (meters)

        c = 1 for a ring or hollow cylinder

        c = 2/5 solid sphere around a diameter

        c = 7/5 solid sphere around a tangent

        c = ⅔ hollow sphere around a diameter

    • jenna2 months agoReport

      Thx!

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