# gr 12 physics?

Light with a wavelength of 610 nm is incident on a metallic surface with a work function of 1.61 eV. Calculate the maximum kinetic energy of the emitted electrons.

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- FiremanLv 72 months agoFavorite Answer
By hf = ф + E(k)

=>E(k) = hc/λ - ф

=>E(k) = [6.63 x 10^-34 x 3 x 10^8]/[610 x 10^-9] - [1.61 x 1.6 x 10^-19]

=>E(k) = 3.26 x 10^-19 - 2.58 x 10^-19

=>E(k) = 0.68 x 10^-19 J OR 0.43 eV

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