promotion image of download ymail app
Promoted

What happens to the force?

In Coulomb's Law, what happens to the force when the distance between the two charges are doubled? The only thing I'm having trouble is what to put into Q1 and Q2 to find what happens to the force.

gets larger (multiplied by 8)

gets smaller (multiplied by 0.0625)

gets larger (multiplied by 4)

gets larger (multiplied by 2)

gets larger (multiplied by 16)

gets smaller (multiplied by 0.125)

gets smaller (multiplied by 0.5)

can't tell since charges are unknown

gets smaller (multiplied by 0.25)

3 Answers

Relevance
  • NCS
    Lv 7
    2 months ago
    Favorite Answer

    Put in Q1 and Q2.

    At original distance d,

    F = k * Q1 * Q2 / d²

    At double the distance,

    F' = k * Q1 * Q2 / (2d)² = ¼ * k * Q1 * Q2 / d² = ¼ * F

    • Commenter avatarLogin to reply the answers
  • 2 months ago

    force drops with square of the distance; doubled distance (2) squared 2^2 = 4, or 1/4 the force or gets smaller multiplied by .25

    • Commenter avatarLogin to reply the answers
  • 2 months ago

    Charge level varies with the inverse square law, like gravity or light intensity.  Multiply by 1/(2^2) or 1/4 or 0.25.

    • Commenter avatarLogin to reply the answers
Still have questions? Get your answers by asking now.