Question about B-Fields?
A single current carrying circular loop of wire (R = 5 cm) is laying flat on a desk. A second, larger current carrying loop (R = 8 cm) is concentric with the first. Determine the magnitude of the net B-field at the center point if both loops carry 2 A of current, but in opposite directions?
Do I find the B field of each of the loops and subtract them from each other...? I'm not sure how that would work in terms of the current being opposite, though. Any input would be GREATLY appreciated!!!
- FiremanLv 72 months ago
By B = µoi/2r
=>B(small) = µoi/2r(small)------------------(i)
& B(big) = µoi/2r(big) ---------------------(ii)
Since direction of i is in opposite direction:
=>B(net) = B(small) - B(big)
=>B(net) = µoi/2 [ 1/r(small) - 1/r(big)]
=>B(net) = (µo x 2)/2 x [1/(5 x 10^-2) - 1/(8 x 10^-2)]
=>B(net) = µo x [7.5]
=>B(net) = 7.5µo