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A gas has a volume of 1.62 L at −21◦C and 141 kPa. At what temperature would the gas occupy 1.18 L at 216 kPa? Answer in units of ◦C.?

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  • 2 months ago

    (-21 + 273) K x (216 kPa / 141 kPa) x (1.18 L / 1.62 L) = 281.19 K = 8.0°C

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