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Help me with Maths IGCSE past paper?

Question 1: A is the point (7, 12) and B is the point (2, -1). Find the length of AB.

I'm in grade 10, and I dont think i have learnt it .. Could you show me the work and the solution?

And also I would like to know what topic its.

Thank uuu

8 Answers

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  • 2 months ago
    Favorite Answer

    Co-ordinate geometry is the topic here.

    It's a case of applying Pythagoras' theorem

    If we sketch the diagram joining A to B and evaluate the difference in the x coordinates and y coordinates, we create a right-angled triangle.

    Difference in x => 7 - 2 = 5

    Difference in y => 12 - (-1) = 13

    We then have AB² = 5² + 13²

    so, AB² = 25 + 169 => 194

    Hence, AB = √194 => 13.9 units

    See diagram below.

    :)>

    Attachment image
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  • 2 months ago

    The solution is as follows:

    Attachment image
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  • 2 months ago

    Use Pythagoras

    AB^2 = (7-2)^" + (12 - - 1)^2

    AB^2 = 5^2 + 13^2

    AB^2 = 25 + 169

    AB^2 = 194

    AB = sqrt(194) = 13.928....

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  • 2 months ago

    It is Pythagorean's theorem in geometry.

    Go to KhanAcademy.org and learn math geometry, trig and algebra. It will take you ~ 1 year if you work at it. It is a series of videos and is very good. Make a notebook and keep notes as you go.

    For this problem The length is sqrt[(7-2)^2+(12+1)^2]=sqrt[(5)^2+(13)^2)]=sqrt[25+169]=sqrt[194]=13.93

    13.93 units

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  • 2 months ago

    I must ask, did you make an attempt to look this up yourself?

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  • 2 months ago

    A is the point (7, 12) and B is the point (2, -1). 

    Find the length of AB.

    Distance Formula: 

    Given the two points (x1, y1) and (x2, y2), 

    the distance d between these points is given by the formula:

    d = sqrt{(x2 - x1)^2 + (y2 - y1)^2}

    d = sqrt(25 +169) = sqrt 194 = 13.92838827718412

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  • 2 months ago

    d = √[ (y2 - y1)^2 + (x2 - x2)^2]

    d = √[ (-1 - 12)^2 + (12 - 7)^2 ]

    d = √[ (-13)^2 + (5)^2 ]

    d = √ (169 + 25)

    d = √ 194 

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  • Anonymous
    2 months ago

    It's just using Pythagoras, which I'm sure you have covered.

    Sketch xy axes and mark A and B.

    Draw a vertical  line through A.

    Draw a horizontal line through B.

    These lines meet at P (7,-1) and ABP is a right-angled triangle with AB the hypotenuse.

    AB² = AP² + BP² = (7-2)² + (12-(-1))² = 194

    AB = √194 = 13.9 approx,

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