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# How many liters if hydrogen (at 744 torr & 24°C) react with 23.0 g of propylene?

I still cannot figure this out

### 2 Answers

- billrussell42Lv 76 months agoFavorite Answer
Propene + hydrogen ➜ propane

C₃H₆ + H₂ ➜ C₃H₈

23 g of H₂ / 2g/mol = 11.5 mol

mole ratio says 1:1, so 11.5 mol of C₃H₆

now many liters of hydrogen (at 744 torr & 24°C)

V = nRT/P = (11.5)(62.36)(273.16+24) / (744) = _____ L

(you have a calculator)

Ideal gas law

PV = nRT

n = number of moles

R = gas constant = 0.08206 (atm∙L)/(mol∙K)

8.314 L∙kPa/mol∙K

0.08314 L∙bar/mol∙K

62.36 L∙torr/mol∙K

62.36 L∙mmHg/mol∙K

T = temperature in kelvins

P = absolute pressure in atm, kPa, bar, torr

V = volume in liters

- Anonymous6 months ago
1 mole of propylene will react with 1 mole of H2.

Moles of propylene =? (About 1/2)

Use the ideal gas equation to find the volume of hydrogen, V = nRT/P. About 10.