How many liters if hydrogen (at 744 torr & 24°C) react with 23.0 g of propylene?
I still cannot figure this out
- billrussell42Lv 76 months agoFavorite Answer
Propene + hydrogen ➜ propane
C₃H₆ + H₂ ➜ C₃H₈
23 g of H₂ / 2g/mol = 11.5 mol
mole ratio says 1:1, so 11.5 mol of C₃H₆
now many liters of hydrogen (at 744 torr & 24°C)
V = nRT/P = (11.5)(62.36)(273.16+24) / (744) = _____ L
(you have a calculator)
Ideal gas law
PV = nRT
n = number of moles
R = gas constant = 0.08206 (atm∙L)/(mol∙K)
T = temperature in kelvins
P = absolute pressure in atm, kPa, bar, torr
V = volume in liters
- Anonymous6 months ago
1 mole of propylene will react with 1 mole of H2.
Moles of propylene =? (About 1/2)
Use the ideal gas equation to find the volume of hydrogen, V = nRT/P. About 10.