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# Physics spring constant?

What is the spring constant of a spring that has a 1.25-kg mass bouncing on it with a frequency 25 Hz?

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- FiremanLv 72 months agoFavorite Answer
Given n = 25 Hz

=>By T = 1/n = 1/25 = 0.04 sec

Thus by T = 2π√[m/k]

=>0.04 = 2 x 3.14 x √[1.25/k]

=>√[1.25/k] = 6.37 x 10^-3

=>1.25/k = (6.37 x 10^-3)^2

=>k = 1.25/(6.37 x 10^-3)^2

=>k = 30811.25 N/m

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- Anonymous2 months ago
omega = 2 * pi * frequency = 50pi /sec

omega = square root of (k/m)

Substitute and find k

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