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Tangent to a circle problem?

Doing my working, i got y = -2/√26X + 21√26/13

I assume b = 2/√26 and c = 21√26/13, but what is a( is it 1)?

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1 Answer

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  • 2 months ago

    y² + x² = m

    2y y’ + 2x = 0

    y’ =  -x/y

    y’ = (14/5)/(7√26/5)

    y’ = ( √26 )/13

    y - 7√26  / 5 = ( √26 )/13 ( x - 14/5 )

    y  = ( √26 )/13 ( x - 14/5 ) + 7√26 / 5

    y = (1/65)√26 (  5x + 77 )

    65y / √26 = 77 + 5x

    y √( 325/2)  = 77 + 5x

    a = 325/2 = 162.5

    b = -5

    c = 77

      

    • Yemi2 months agoReport

      What is 2y y' and where did you get it and 2x from and why is it equal to 0

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