# Tangent to a circle problem?

Doing my working, i got y = -2/√26X + 21√26/13

I assume b = 2/√26 and c = 21√26/13, but what is a( is it 1)?

### 1 Answer

Relevance

- King LeoLv 72 months ago
y² + x² = m

2y y’ + 2x = 0

y’ = -x/y

y’ = (14/5)/(7√26/5)

y’ = ( √26 )/13

y - 7√26 / 5 = ( √26 )/13 ( x - 14/5 )

y = ( √26 )/13 ( x - 14/5 ) + 7√26 / 5

y = (1/65)√26 ( 5x + 77 )

65y / √26 = 77 + 5x

y √( 325/2) = 77 + 5x

a = 325/2 = 162.5

b = -5

c = 77

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What is 2y y' and where did you get it and 2x from and why is it equal to 0