# Two resistors A and B are connected in parallel across a 12V battery. The current through B is found to be 1.6A. When the two resistors are?

connected in series to the 12 V battery,

a voltmeter connected across resistor A measures a voltage of 6.7V.

Find the resistance of B.

Answer in units of Ω.

Find the resistance of A.

Answer in units of Ω.

### 1 Answer

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- NCSLv 72 months agoFavorite Answer
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When in parallel, the voltage drop across both resistors must be the same, so for B,

R = V / I = 12V / 1.6A = 7.5 Ω ◄ resistance B

When in series, if the drop across A is 6.7 V, then the drop across B must be 5.3 V. Find the current:

I = V / R = 5.3V / 7.5Ω = 0.71 A

That must also be the current in A, so

R = 6.7V / 0.71A = 9.5 Ω ◄ resistance A

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