promotion image of download ymail app
Promoted

A cylindrical roll of sod is being unrolled such that its volume is decreasing at a rate of 2500 cm^3/s. If the length of the roll is ?

45 cm, at what rate is the radius of the roll decreasing when it has reached a radius of 12.5 cm? 

1 Answer

Relevance
  • Bryce
    Lv 7
    2 months ago
    Favorite Answer

    V= π*r^2*h, h= 45 cm

    dV/dt= 90πr*dr/dt

    2500= 90π*12.5*dr/dt

    dr/dt= 250/(112.5π)≈ 0.7074 cm/s

    • Commenter avatarLogin to reply the answers
Still have questions? Get your answers by asking now.