A cylindrical roll of sod is being unrolled such that its volume is decreasing at a rate of 2500 cm^3/s. If the length of the roll is ?
45 cm, at what rate is the radius of the roll decreasing when it has reached a radius of 12.5 cm?
- BryceLv 72 months agoFavorite Answer
V= π*r^2*h, h= 45 cm
dr/dt= 250/(112.5π)≈ 0.7074 cm/s
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