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Why can’t we write -a=b^x/y ?

If we are given to solve a^y=b^x then we solve it by making a=b^x/y. My question is if y is even why can’t we write -a instead of a in LHS because if we are given 4= x^2 we write x=+2 or -2? I am very confused, so please help.

1 Answer

  • ?
    Lv 7
    1 year ago
    Favorite Answer

    x^2 = y  ...  y is a variable, not a constant like 4

    ...  different rules apply

      a^y = b^x

        a = b^(x/y)  until you know a number value for b and y (which has become a root) we don 't know if the answer is pos, neg, or imaginary.

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